Posted by news.cogeco.ca on 08/20/06 13:36

Here is my code below and I am currently have php version 4.4.4 installed.

$SQL="Select field1 from table where field1 like '%%%1\$s%%'";
$Str='Bob';

sprintf($SQL, $Str);

The sprintf doesn't like the %% double percent signs to use it in a like
statment any ideas?

Thanks...

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