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Posted by Andrew Poelstra on 08/22/06 17:34
"comp.lang.php" <phillip.s.powell@gmail.com> writes:
> I have no idea why this is happening and I need someone to explain this
> to me at the simplest level absolutely possible (pretend I'm a 10-year
> old and explain it that way, please!)
>
> This class method:
>
> PHP Code:
> /**
> * Perform an array scan
> *
> * @access private
> * @param array $array
> * @see vname
> */
> function &array_scan(&$array) {
> if (is_array($array) && @sizeof($array) > 0) {
Instead of indenting the whole function, you may wish to just add a
premature return and negate the test:
if (!isarray ($array) || @sizeof ($array) == 0)
return;
> print_r("sizeof(" . vname($array) . ") = " . sizeof($array) .
> "<P>");
> $index = 1;
> foreach ($array as $key => $val) {
How about you just indent two more spaces after each {? This style is
very erratic and hard to read.
This appears to be your only loop; try replacing the body with something
simple like
echo "Key: $key<br />Value: $val<br /><br />\n";
and see if the problem persists.
> print_r("index = $index<P>"); $index++;
> $this->setData($val);
> print_r("key = $key and val = $val and this->data =
> $this->data and array name = " . vname($array) . "<P>");
> $this->scan($key, vname($array));
> $array[$key] = $this->getData();
> }
> }
> }
>
>
> Constantly produces the following results:
>
> Quote:
> sizeof(_POST) = 5
>
> index = 1
>
> key = username and val = phillip and this->data = phillip and array
> name = _POST
>
> this->data = phillip
>
> index = 2
>
> key = username and val = phillip and this->data = phillip and array
> name = _POST
>
> this->data = phillip
>
> index = 3
>
> ...// and so on and so on.. as high as 200,000 at times and still
> doesn't quit!!
>
Is $index a reserved variable, or something that foreach() might be
using internally? I assume not, but try renaming or removing it and
see if that helps any.
--
Andrew Poelstra <http://www.wpsoftware.net/projects>
To reach me by email, use `apoelstra' at the above domain.
"Do BOTH ends of the cable need to be plugged in?" -Anon.
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