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Posted by Richard Davey on 10/20/43 11:18
Hello jack,
Friday, June 10, 2005, 3:11:17 AM, you wrote:
jj> All the first part of the query works and inserts records into the
jj> database, and it's when I try to get mysql_insert_id () that I seem to
jj> run into trouble. Ah. ave I not yet run the first query? The part of
jj> the code that actually runs it was given to me in a class and I don't
jj> quite understand how it's suppose to be working ...
You didn't appear to be running the query before trying to get the
last ID - so there's obviously not going to be an ID which will cause
the subsequent queries to fail, as they rely on them.
jj> foreach ($media_types[] as $type)
jj> {
jj> $query .= "INSERT INTO media_art
jj> (media_art_id,media_id, art_id)
jj> VALUES ('','" . $type . "','" . $art_id . "')";
jj> // perform query here
Before you run the query you need to check what $type contains - you
don't want to perform an insert for every single checkbox, only for
those that have actually been checked.
Also - you don't appear to be actually performing the query at all
here - you're just appending it onto the $query string. You can't do
it like this if you need the IDs returned - you have to actually DO
the query THEN get the ID, then move onto the next stage.
So at this point in your code you need to actually perform a query.
Best regards,
Richard Davey
--
http://www.launchcode.co.uk - PHP Development Services
"I do not fear computers. I fear the lack of them." - Isaac Asimov
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