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Posted by Vinay Nagrik on 09/08/06 00:52
Hello group members,
I want to send a file "a.b" and I want server to save this file on the
server in
filename "abcde" then I will send the file content as buffer and
include the following
header
Content-Disposition: attachment; filename=abcde;
and if I want to send a stream I will have the following header
Content-Disposition: inline
I want the server to echo the content of the buffer and save the file
in the filename variable.
I am aware of the form interface, but I do not want the server side
script to read form data.
Instead I want to telnet to the server which can take the post request
and follow my wishes.
The following two scripts do not serve the purpose, What need I
change in these scripts so
that I can do the needful.
<?php
print_r($_POST);
?>
************** to echo the content and
<?php
$uploaddir = '/var/www/uploads/';
$uploadfile = $uploaddir . basename($_FILES['userfile']['name']);
echo '<pre>';
if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
echo "File is valid, and was successfully uploaded.\n";
} else {
echo "Possible file upload attack!\n";
}
echo 'Here is some more debugging info:';
print_r($_FILES);
print "</pre>";
?>
**************to save the file
Thanks in advance.
nagrik
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