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Posted by KrunoG on 10/11/06 12:04
"Diogenes" <nospam@nospam.net> wrote in message
news:EZPWg.119267$1T2.96496@pd7urf2no...
> Kind readers,
>
> I am currently developing an app with PHP 5 & MySql 5.
>
> The following select statement works as expected from
> the MySql command line but produces an error when run from PHP.
>
> SELECT pkey, Name FROM tracks WHERE artist="Rolling Stones"
> AND pkey NOT IN (SELECT Song FROM requests WHERE client="jim")
>
> The error produced by PHP is
>
> "Query failed: You have an error in your SQL syntax; check
> the manual that corresponds to your MySQL server version for
> the right syntax to use near ')' at line 1"
>
> I've done a workaround by substituting the pkey values in
> the parentheses in place of the subquery SELECT statement,
> but I can't figure out why the above query does not work in
> PHP but does in MySQL.
>
> The versions of each app read as follows ...
>
> >mysql -V
> mysql Ver 14.12 Distrib 5.0.22, for Win32 (ia32)
>
> >php -v
> PHP 5.2.0-dev (cli) (built: Jul 19 2006 16:20:24)
> Copyright (c) 1997-2006 The PHP Group
> Zend Engine v2.2.0, Copyright (c) 1998-2006 Zend Technologies
>
> Any insight would be much appreciated.
>
> Cheers
> Jim
Try first to use single quotation marks instead of double.
Double quotations are used for variables with blank spaces in their names.
Try and reply, I'm searching for one similar sql I used recently
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