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Posted by Moot on 10/18/06 14:07
jodleren wrote:
> I have 2 pieces of code, where one works, another does not, even they
> should be the same
>
> echo " <td> $s $s2</td><td>$s-";
> echo $s+$s2." </td></tr>\r\n";
>
> which can be truncated to
>
> echo " <td> $s $s2</td><td>$s-".$s+$s2." </td></tr>\r\n";
>
> All in one line, but then the first part in the "" will not be printed,
> result: 45</td></tr> - a funny table.
> There should be no difference, but there is.
>
> $s and $s2 are integer, the entire table is for debugging. The error is
> known and I can work around this.
>
> But i cannot explain it.
>
> BR
> Sonnich
When doing math within a string concatenation, you need to use
parethesis.
So your second example becomes:
echo " <td> $s $s2</td><td>$s-". ($s+$s2) ." </td></tr>\r\n";
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