|
Posted by greedo on 11/26/06 15:44
Hi, first of all, please bear with me, I don't really know a great deal
about php programming, as will be painfully obvious from the code
snippet I'm gonna post. But I need this problem solved, and I can't
find the information I need (or maybe I can't understand it). So here's
the thing:
What I have is a range of integers, and I need those whose digits
alternate between odd and even. Example: 123456789. For that purpose I
have this thingy here:
settype($zee, "string");
if (($zee[0] % 2 != 0) && ($zee[1] % 2 == 0))
{
echo $zee . "<br />";
}
Just to be precise: I want to have $zee echoed, if the first digit is
odd and the second is even.
Now, this doesn't work, because apparently the second condition is
never true. I don't get why. Because if I change the "==" in the second
condition to "!=" (that is to say I want both digits to be odd), then
it works fine! Can someone help me fix this?
PS:
When the conditions are put like this:
if (($zee[0] & 1) && ($zee[1] & 0))
the exact same thing happens: it works with two odd conditions, but not
with one odd, one even.
Navigation:
[Reply to this message]
|