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Posted by Mladen Gogala on 11/26/06 17:33
On Sun, 26 Nov 2006 07:44:53 -0800, greedo wrote:
> Hi, first of all, please bear with me, I don't really know a great deal
> about php programming, as will be painfully obvious from the code
> snippet I'm gonna post. But I need this problem solved, and I can't
> find the information I need (or maybe I can't understand it). So here's
> the thing:
>
> What I have is a range of integers, and I need those whose digits
> alternate between odd and even. Example: 123456789. For that purpose I
> have this thingy here:
>
> settype($zee, "string");
> if (($zee[0] % 2 != 0) && ($zee[1] % 2 == 0))
> {
> echo $zee . "<br />";
>
> }
>
> Just to be precise: I want to have $zee echoed, if the first digit is
> odd and the second is even.
>
> Now, this doesn't work, because apparently the second condition is
> never true. I don't get why. Because if I change the "==" in the second
> condition to "!=" (that is to say I want both digits to be odd), then
> it works fine! Can someone help me fix this?
>
> PS:
> When the conditions are put like this:
> if (($zee[0] & 1) && ($zee[1] & 0))
> the exact same thing happens: it works with two odd conditions, but not
> with one odd, one even.
Your type conversion is a mortal sin and may cost you dearly when you meet
the Great Programmer. Repent, o sinner, change thy evil ways and do
something like this:
$zere="345678";
$zee=preg_split('//',$zere,-1,PREG_SPLIT_NO_EMPTY);
if (($zee[0] % 2 != 0) && ($zee[1] % 2 == 0))
{
echo "zere=$zere\n";
}
else echo '$zee[0]=',$zee[0]," ",'$zee[1]=',$zee[1],"\n";
BTW, your assumption about C-ish equivalent between strings and arrays
does not hold water in the PHP world. Your "settype" trick would be neat,
had it worked.
--
http://www.mladen-gogala.com
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