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Posted by Matthew Weier O'Phinney on 09/28/90 11:19
* Robert Cummings <robert@interjinn.com> :
> On Thu, 2005-06-23 at 13:36, Matthew Weier O'Phinney wrote:
> > * Robert Cummings <robert@interjinn.com> :
> > > On Thu, 2005-06-23 at 11:32, Matthew Weier O'Phinney wrote:
> > > > The above notation is unnecessary when developing in PHP5, as objects in
> > > > PHP5 are passed by reference by default. However, in PHP4, this was
> > >
> > > Not entirely, there's still a subtle difference in PHP5 between
> > > assigning an object with = versus assigning with = &.
> >
> > Would you mind explaining the difference? I've seen nothing in the docs,
> > to indicate that assigning objects with =& in PHP5 is necessary, or even
> > desired. My experience with PHP5 hasn't shown this either. I'd be
> > interested to know to what you refer.
>
> See for yourself when running the following script:
>
> <?php
>
> class a
> {
> }
>
> class b
> {
> }
>
> $aObj = new a();
> $bObj = new b();
>
> $foo1 = $aObj;
> $foo2 = $aObj;
> $foo3 = $foo1;
> $foo4 = &$foo2;
>
> echo "------------------\n";
> print_r( $foo1 );
> print_r( $foo2 );
> print_r( $foo3 );
> print_r( $foo4 );
>
> $foo1 = $bObj;
> $foo2 = $bObj;
>
> echo "------------------\n";
> print_r( $foo1 );
> print_r( $foo2 );
> print_r( $foo3 );
> print_r( $foo4 );
>
> $foo1 = &$aObj;
> ?>
This doesn't demonstrate what the OP was talking about, which is initial
assignment of an object using a reference operator. The results of this
make perfect sense to me -- the references are passed exactly as I would
expect.
Let me rephrase my question to you: is there a reason to do the initial
object assignment using a reference operator using PHP5? I.e., is there
a good reason to do this:
$foo =& new Foo();
instead of:
$foo = new Foo();
I haven't seen any reason to do the former case using PHP5.
--
Matthew Weier O'Phinney | WEBSITES:
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