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Posted by Robert Cummings on 09/28/35 11:19
On Thu, 2005-06-23 at 15:28, Matthew Weier O'Phinney wrote:
> * Robert Cummings <robert@interjinn.com> :
> > On Thu, 2005-06-23 at 13:36, Matthew Weier O'Phinney wrote:
> > > * Robert Cummings <robert@interjinn.com> :
> > > > On Thu, 2005-06-23 at 11:32, Matthew Weier O'Phinney wrote:
> > > > > The above notation is unnecessary when developing in PHP5, as objects in
> > > > > PHP5 are passed by reference by default. However, in PHP4, this was
> > > >
> > > > Not entirely, there's still a subtle difference in PHP5 between
> > > > assigning an object with = versus assigning with = &.
> > >
> > > Would you mind explaining the difference? I've seen nothing in the docs,
> > > to indicate that assigning objects with =& in PHP5 is necessary, or even
> > > desired. My experience with PHP5 hasn't shown this either. I'd be
> > > interested to know to what you refer.
> >
> > See for yourself when running the following script:
> >
> > <?php
> >
> > class a
> > {
> > }
> >
> > class b
> > {
> > }
> >
> > $aObj = new a();
> > $bObj = new b();
> >
> > $foo1 = $aObj;
> > $foo2 = $aObj;
> > $foo3 = $foo1;
> > $foo4 = &$foo2;
> >
> > echo "------------------\n";
> > print_r( $foo1 );
> > print_r( $foo2 );
> > print_r( $foo3 );
> > print_r( $foo4 );
> >
> > $foo1 = $bObj;
> > $foo2 = $bObj;
> >
> > echo "------------------\n";
> > print_r( $foo1 );
> > print_r( $foo2 );
> > print_r( $foo3 );
> > print_r( $foo4 );
> >
> > $foo1 = &$aObj;
> > ?>
>
> This doesn't demonstrate what the OP was talking about, which is initial
> assignment of an object using a reference operator. The results of this
> make perfect sense to me -- the references are passed exactly as I would
> expect.
>
> Let me rephrase my question to you: is there a reason to do the initial
> object assignment using a reference operator using PHP5? I.e., is there
> a good reason to do this:
>
> $foo =& new Foo();
>
> instead of:
>
> $foo = new Foo();
>
> I haven't seen any reason to do the former case using PHP5.
Your original response said that the above notation was unneccessary, I
took that to mean the & operator for reference. Looking back I see ow
that your comment was ambiguous, and I agree there is no need for the &
when assigning a new object. I was merely clarifying that references and
normal assignment are not synonymous for objects in PHP 5.
Cheers,
Rob.
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