|  | Posted by Ruben van Engelenburg on 01/11/07 11:57 
Dave Nash wrote:
 > $query = "select * from categories WHERE parentid = $catid";
 > $result = mysql_query($query) or die ("Couldn't execute query: " .
 > mysql_error());
 > echo "$query";
 >
 > Table is categories
 >
 > CATID
 > PARENTID
 >
 > Im trying to show all categories where the PARENTID value is the same
 > as the CATID value.
 
 It could be that the variable $catid is empty, causing the query to be
 invalid.
 I'm not sure where $catid is being set in your script because you didn't
 post that part, hence my question to echo the $query var.
 
 Ruben.
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