Posted by Curtis on 02/01/07 03:50

On Wed, 31 Jan 2007 18:57:37 -0800, <tmattevans@gmail.com> wrote:

> Hi All --
>
> I had never even looked at PHP until a few hours ago. I'm trying to
> get someone else's code to work. My sense is that the error will be
> pretty obvious to someone familar with the language. The lines of
> code below don't work -- some of the PHP is actually shown in the
> browser window. What am I missing?
>
> Thanks in advance....
>
> Matt
>
> echo ("<input type=3D\"hidden\" name=3D\"x_description\" value=3D\"" .=

> $x_Description . "\">\n" );
> echo ("<input type=3D\"hidden\" name=3D\"x_login\" value=3D\"" . $logi=
nid .
> "\">\n");
> echo ("<input type=3D\"hidden\" name=3D\"x_amount\" value=3D\"" . $amo=
unt .
> "\">\n");
>

Your code needs to be wrapped in PHP tags: <?php /* execution */ ?>

Before running this code, did you try a "hello, world" program to check =
if =

everything is working as it should?

-- =

Curtis, http://dyersweb.com

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