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Posted by Taras_96 on 02/08/07 07:24
> Next, I tried
>
> echo bin2hex(addcslashes("\0","\0")); which gave 5c 30 30 30, which is
> a backslash followed by 3 spaces. What's happening here? I would have
> thought that the output would be
>
> 5c 00 (backslash followed by a null)
>
> Taras
Meh, I re-read the manual more closely and realised that: "while other
non-alphanumeric characters with ASCII codes lower than 32 and higher
than 126 converted to octal representation."
so 5c 30 30 30 = \ octal representation of 0
or, if the byte x01 was escaped, the result would be
5c 30 30 31 = \001 = \ octal representation of 01
What is the point of converting to an octal representation? Where
would it be used? I've never heard of this being used in the c
language..
Taras
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