Posted by Rik on 02/15/07 15:38

fabrice régnier <regnier.fab@free.fr> wrote:
>> Either by a loop:
>> $filtered = array()
>> foreach ($res as $key => $item){
>> if($res['age']!=0) $filtered[] = $item;
>> //or preserve keys by $filtered[$key] = $item;
>> }
>> Or indeed by array_filter:
>> $filtered = array_filter($res,create_funtion('$v,$k','return
>> $v['age']!=0;'));
>
> I've tested your 2 solutions and both doesn't work.
>
> First solution gives me an empty array as a result.
> Second solution gives me a syntaxic error.
>
> Maybe you forgot something ? Thanx, anyway.


Allthough I usually respond with a lot of code, I do not test this. It's
an insight in how you can solve your problem, if you want me to write your
code for you you'll have to pay the usual rate. Getting an answer is not
like paying for a full working code, you'll have to do your own
error-hunting and implementation. I suggest some reading material:
<http://www.catb.org/~esr/faqs/smart-questions.html>.

FYI: What was wrong?
First example:
if($res['age']!=0) $filtered[] = $item;
should be
if($item['age']!=0) $filtered[] = $item;

Example:
$filtered = array_filter($res,create_funtion('$v,$k','return
($v[\'age\']!=0);'));

Both mistakes are easily spotted with a minimum amount of effort.
--
Rik Wasmus

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