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Posted by myaashik on 03/14/07 20:35
Hello! All I have a Error message saying that:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
result resource in /home/rocks/public_html/colorado3.php on line 32
I have error on this code below:
<html>
<head>
<title> Colorado</title>
</head>
<body>
<h1>Social Security Offices</h1>
</html>
<?php
$con = mysql_connect("localhost","admin","*******");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("office", $con);
$id = $_GET['id'];
$result = mysql_query("SELECT * FROM sso WHERE state = $id");
echo "<table border='2'>
<tr>
<th>Address1</th>
<th>Address2</th>
<th>City</th>
<th>State</th>
<th>Zip</th>
<th>Telephone</th>
</tr>";
while($row = mysql_fetch_array($result)) {
$neprocks_office = $row->neprocks_office; $addr_st1 = $row->addr_st1;
$addr_st2 = $row->addr_st2; $city = $row->city;
$state = $row->state; $zip = $row->zip; $telephone = $row->telephone;
echo "<tr>";
echo "<td>" . $row['addr_st1'] . "</td>";
echo "<td>" . $row['addr_st2'] . "</td>";
echo "<td>" . $row['city'] . "</td>";
echo "<td>" . $row['state'] . "</td>";
echo "<td>" . $row['zip'] . "</td>";
echo "<td>" . $row['telephone'] . "</td>";
echo "</tr>";
}
echo "</table>";mysql_close($con);
?>
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