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Posted by Lennart Anderson on 03/21/07 19:13
"Rami Elomaa" <rami.elomaa@gmail.com> skrev i meddelandet
news:etrvf5$fjk$1@nyytiset.pp.htv.fi...
> Lennart Anderson kirjoitti:
>> I want to present a table with main data. Each revord will have a field
>> acting like a link to a new page with detailed data on the selected
>> record. My problem is that I can't get the record-ID parsed into the link
>> parameter. Whatever I do will just let my $_GET['id'] give me what is
>> after the equal-sign in the link prameter.
>> The code is:
>> while($row = mysql_fetch_object($result))
>> {
>> $mid = ($row->catid);
>> $name = ($row->catname);
>> echo '<tr>';
>> echo '<td >' . $mid . '</td>';
>> echo '<td>' . '<a href="advertinfo.php?id=$mid">' . $name . '</a></td>';
>> echo '</tr>';
>> }
>> echo '</table>';
>>
>> In this case the $_GET on advertinfor.php will only give me $mid.
>> I think the problem might be in the quotes but I also think I have tested
>> every possible combinaion without success.
>> Any solution or hint is very much appreciated.
>
> The difference between ' and " is that php variables inside "" are parsed
> but inside '' they are not. So "$foo" will be parsed as $foo the variable,
> but '$foo' is seen as a literal string, a dollar sign followed by the
> string foo.
>
> --
> Rami.Elomaa@gmail.com
> "Olemme apinoiden planeetalla."
Rami
Thank you
I thought I knew that but obviously I did a mistake. In such a link there
are a lot of " and ' together with .-dots. I thought I have tried all
combinations but ....
OK, you learn by mistakes, don't you. I am still a newbie.
Well, now I have got the solution to that problem but I am very convinced
that I will meet new problems and then it is very good to have found this
group.
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