Posted by Hendri Kurniawan on 04/07/07 21:01

Steve wrote:
>
> you have heard of tertiary operators, right?
>
> g = y > 170 && g == 0 ? 1 : 0;
> q = q + 5 * (g ? -1 : 1);
> y += q;
>

Sorry I though it was "ternary" operator, not "tertiary"... Which one is
correct?
Hendri

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