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Re: $_GET request -> variable -> object? -> function

Posted by Jerry Stuckle on 04/14/07 13:42

strawberry wrote:
> On Apr 13, 6:23 pm, Rami Elomaa <rami.elo...@gmail.com> wrote:
>> Vince Morgan kirjoitti:
>>
>>
>>
>>> "strawberry" <zac.ca...@gmail.com> wrote in message
>>> news:1176450464.524325.95990@n59g2000hsh.googlegroups.com...
>>>> On Apr 13, 1:51 am, "strawberry" <zac.ca...@gmail.com> wrote:
>>>>> I'm trying to extend a class (written by others) and was wondering if
>>>>> there's a standard a way of passing a $_GET request to a class. Here's
>>>>> what I have (see below). If I hardcode $where, something like
>>>>> $where = " WHERE `firstname` = 'John' "
>>>>> and then pass it as an argument into the scope of a 'select' function
>>>>> then it works fine, but otherwise the query just appears to hang.
>>>>> I'm deliberately not including the class or class extender at this
>>>>> stage, but I'll add them to this thread later if required.
>>>>> foreach ($_GET as $condition_key => $condition_value) {
>>>>> $condition[] =" $condition_key = '$condition_value' ";
>>>>> }
>>>>> if(is_null($condition)){
>>>>> $where = " WHERE 1 ";
>>>>> }else{
>>>>> $conditionString = implode('AND', $condition);
>>>>> $where = " WHERE $conditionString ";
>>> The line above is looking for a value from a field named $conditionString.
>> No, it doesn't. Variables inside a double quoted string are parsed. It's
>> perfectly valid code. The example you gave would also work, but it's
>> totally unnecessary.
>>
>> Just try this and you'll learn something fun:
>>
>> <?php
>>
>> $cat = 'dog';
>>
>> echo "I have an animal in my hand and the animal is a $cat. <br />";
>> echo 'I have an animal in my hand and the animal is a $cat. <br />';
>>
>> ?>
>>
>> --
>> Rami.Elo...@gmail.com
>>
>> "Wikipedia on vähän niinq internetin raamattu, kukaan ei pohjimmiltaan
>> usko siihen ja kukaan ei tiedä mikä pitää paikkansa." -- z00ze
>
> Thanks Rami,
>
> I knew from the echoes that my statements were valid. Unfortunately,
> the mysrc class doesn't seem to agree with me :-(
>
> To recap. No matter what I try I just can't seem to pass this...
>
> foreach ($_GET as $condition_key => $condition_value) {
> $condition[] =" `$condition_key` = '$condition_value' ";
> $condition_keys[] = "$condition_key";
> $condition_values[] = "'$condition_value'";
> }
> if(is_null($condition)){
> $conditionString = " 1 ";
> }else{
> $conditionString = implode('AND', $condition);
> $conditionKeysString = implode(',',$condition_keys);
> $conditionValuesString = implode(',',$condition_values);
> }
>
> as arguments to this...
>
> class mysrc extends drasticsrcmysql {
> protected function select($conditionString){
> $query = "SELECT * FROM $this->table WHERE $conditionString";
> $res = mysql_query($query . $this->orderbystr, $this->conn) or
> die(mysql_error());
> return ($res);
> }
>
> protected function add($conditionKeysString,$conditionValuesString){
> $query = "INSERT INTO $this->table ($conditionKeysString) VALUES
> ($conditionValuesString)";
> mysql_query($query, $this->conn) or die(mysql_error());
> if (mysql_affected_rows($this->conn) == 1) return(true); else
> return(false);
> }
>
> ...unless I pass a bogus column name: Unknown column
> 'false_column_name' in 'where clause'
>

Without trying to figure out what all this convoluted code does (I'd
never do it that way - simplicity is better) - what do you get when you
echo $query?

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
==================

 

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