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Posted by joe on 04/16/07 20:22
Thanks Iktorn
I ended up doing $where_clause_array = split(" ",$where_clause);
$where_clause = "";
foreach ($where_clause_array as $t) {
$where_clause = $where_clause . " " . preg_replace("/
^'([1-9]+)'$/","$1",$t);
}
I tried using echo preg_replace("/'([0-9]+)'/","$1",$txt)."\n"; but
It did not work. I got stuck with another preg_rplace trying to
replace ('123123','somethingelse for (123123,'somethingelse. If I
could make $sql = preg_replace("/'([0-9]+)'/","$1",$sql) work may be
that would take care of all instances of numbers surrounde by quotes.
On Apr 12, 11:12 pm, iktorn <s...@phpfreelancer.net> wrote:
> Aerik napisał(a):
>
> > On Apr 12, 5:47 pm, "joe" <jcha...@gmail.com> wrote:
> >> hello I have a string that has values in quotes 'hello' 'here' '199'
> >> 'something else'
>
> >> I need to remove the quotes only when they are around numbers.
> >> To make the string lookg like 'hello' 'here' 199 'something else'
> >> any ideas on how to do this? thanks.
>
> > Hm... use a regular expression, I'm thinking preg_replace ought to do
> > the trick...
>
> > Aerik
>
> <?php
>
> $txt = array("'sdfsdfsd'","'as34444'","'234sdfd'","'2344'");
> foreach ($txt as $t) {
> echo preg_replace("/^'([0-9]+)'$/","$1",$t)."\n";
>
> }
>
> $txt = "'sdfsdfsd' 'as34444' '12' '234sdfd' '2344'";
> echo preg_replace("/'([0-9]+)'/","$1",$txt)."\n";
>
> --
> Wiktor Walchttp://phpfreelancer.net
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