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Posted by Captain Paralytic on 04/23/07 15:52
On 23 Apr, 16:45, Captain Paralytic <paul_laut...@yahoo.com> wrote:
> On 23 Apr, 15:24, Rob <nos...@plea.se> wrote:
>
>
>
>
>
> > Hello,
>
> > When i use the following query:
>
> > $sql = "SELECT * FROM table WHERE 1 AND project like '%$zoek%' and publi
> > NOT like 'no' order by jaar DESC LIMIT 0, 100";
>
> > I get what i want: all projects named '%$zoek%' where publi is not like
> > no.
>
> > However, when i want that '%$zoek%' is not only to be searched for in
> > project but also in locatie I use the next query:
>
> > $sql = "SELECT * FROM table WHERE 1 AND project like '%$zoek%' OR
> > locatie like '%$zoek%' and publi NOT like 'no' order by jaar DESC LIMIT
> > 0, 100";
>
> > This does not do the thing I want:
> > records where publi is no are shown where I want them to be hidden.
>
> > Where do things go wrong?
>
> > Rob
>
> Your problem is operator precedence.
> See:http://dev.mysql.com/doc/refman/5.0/en/operator-precedence.html
> What you need to do is:
>
> $sql = "SELECT * FROM table WHERE 1 AND (project like '%$zoek%' OR
> locatie like '%$zoek%') and publi NOT like 'no' order by jaar DESC
> LIMIT
> 0, 100";
>
> Note the brackets.- Hide quoted text -
>
> - Show quoted text -
By the way, I find queries are far easier to read when they're laid
out like:
$sql = "
SELECT
*
FROM `table`
WHERE
(`project` LIKE '%$zoek%' OR `locatie` LIKE '%$zoek%')
AND `publi` NOT LIKE 'no' ORDER BY `jaar` DESC
LIMIT
0, 100";
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