Posted by Marcos Mendon�a on 09/28/07 11:20

Hi list

I need help to solve a preg_replace() problem.

I have a snippet of html code that contains some links.

I have an array thats contains all links inside that snippet of html code.

What i need to do is replace all the links in the code by another on.

So this is what i´m trying to do:

//links that should be replaced
$url = array(
array("id" => 0, "url" => "http://www.silika.com.br/conarh/mala3"),
array("id" => 1, "url" => "http://www.conarh.com.br"),
array("id" => 2, "url" =>
"http://www.conarh.com.br/main_frameset.php?secao=congresso&idioma=port&pagina=http://www.conarh.com.br/programacao/pub/index.php?tipo_barra=laranja"),
array("id" => 3, "url" =>
"http://www.conarh.com.br/main_frameset.php?secao=congresso&idioma=port&pagina=http://www.conarh.com.br/mensagem/pub/mensagem.php?id_mensagem=insc_temp&tipo_barra=laranja"),
array("id" => 4, "url" =>
"http://www.silika.com.br/conarh/patrocinio/patrocinio.htm"));

$escape_chars = array("?", "/");
$escaped_chars = array("\?", "\/");

$matches = array();

foreach ($url as $link) {
$pattern = "/" . str_replace($escape_chars, $escaped_chars, $link["url"]) ."/";
$newurl = URL_LINKS."linkId=".$link["id"]."&rId=1";
$body_html = preg_replace($pattern, $newurl, $body_html, 1);
}

This works fine for links with id 0, 1 and 4. But i haven´t been able
to figure out how to match and replace links with id 2 and 3.

How do I get my regex to match and replace those links as well? Any
help appreciated.

Thanks.

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