| 
 Posted by bokke on 05/07/07 04:08 
Hi, 
 
I am trying to create a variable but it just will not work.  Anyone 
see the error? 
 
<? 
$query = "SELECT Name FROM dataAA WHERE 
NameId='".mysql_real_escape_string($_GET["Id"])."'"; 
$result = mysql_query($query) 
	or die ("no can do."); 
			while($row = mysql_fetch_array($result)) 
			{ 
 
			$Name = "echo $row["Name"]"; 
			} 
			?>
 
  
Navigation:
[Reply to this message] 
 |