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Posted by Edward Vermillion on 07/06/05 22:35
On Jul 6, 2005, at 2:07 PM, Ryan A wrote:
> Hi,
>
> I'm confused, this should give me the age as 17 instead of 16...but it
> does
> not...any ideas why?
>
> <?php print date("Y:m:d");
> $age="1988-07-06";
>
> $day1=strtotime($age);
> $day2 = strtotime(date("Y-m-d"));
> $dif_s = ($day2-$day1);
> $dif_d = ($dif_s/60/60/24);
> $age = floor(($dif_d/365.24));
>
> echo $age;
> ?>
>
> Thanks,
> Ryan
>
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>
If I change $day2 to =time(); instead of strtotime() I get 17. Could be
some weirdness going on with using date()?.
Edward Vermillion
evermillion@doggydoo.net
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