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Posted by Geoff Berrow on 06/20/07 08:22
Message-ID: <1182325982.532226.144310@i13g2000prf.googlegroups.com> from
James_sgp contained the following:
>On Jun 20, 2:58 pm, Geoff Berrow <blthe...@ckdog.co.uk> wrote:
>> Message-ID: <1182306258.201378.288000@j4g2000prf.googlegroups.com> from
>> James_sgp contained the following:
>>
>> >The problem is that the variable
>> >$max_depth isn`t updated when it is written into the database, hence
>> >the original value is always there.
>>
>> Then you have to do the debugging all of us do. If you have
>> something like
>> $sql= "INSERT... ";
>>
>> Then add
>> echo $sql;
>> to see whether the variable is making it to the insert statement
>I have...
>The SQL query contains the old value, while is i 'echo' the variable
>before making the SQL staement it contains the new number!
so you've done
if(strcmp($distance,"ft")==0) $max_depth=$max_depth/3.28;
echo $max_depth;
$sql= "INSERT... $max_depth ... ";
echo $sql;
and $max_depth is different in the INSERT statement?
--
Geoff Berrow 0110001001101100010000000110
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