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Posted by shimmyshack on 06/28/07 18:33
On Jun 28, 7:17 pm, desmond <desm...@zeouane.org> wrote:
> shimmyshack <matt.fa...@gmail.com> wrote:
> > On Jun 28, 2:53 pm, desmond <desm...@zeouane.org> wrote:
> >> .. by 'works', I mean that thera are no errors. Unfortunately, there's no
> >> output either. :-(
>
> >> Here is the HTML that I have in 'test.php' ...
>
> >>http://www.flickr.com/photo_zoom.gne?id=649529794&size=o
>
> >> Here is the php code in the file select.php ...
>
> >>http://www.flickr.com/photo_zoom.gne?id=649529810&size=o
>
> >> When i call up test.php' from my webbrowser, I enter say 'tom' and I get no
> >> results. $dbname _is_ populated and there _is_ a user in there called
> >> 'tom'.
>
> >> Can someone advise..? Thanks
>
> >> [1] I hope this is the right forum..
>
> > your markup is incorrect you need
> > name="first_name" rather than
> > id=....
> > same goes for them all
>
> > also you have {['country']} rather than {$row['country']}
>
> > also where are you getting $first_name from in the query?
> > do you set it to
>
> > $first_name = mysql_string_real_escape( $_GET['first_name'] );
>
> > you know the form uses GET if you dont specify otherwise.
>
> > your code is shall we say not quite all there yet, I would look at
> > some examples online and then adjst them to suit your needs.
>
> OK, typos corrected, the code looks like this (no more screenshots)..
>
> --- test.php (this is the HTML one) ---
> <form action="select.php" method="post">
>
> <h6>
>
> <label for="first_name">First Name: </label>
> <input type="text" name="first_name"><br>
> <label for="second_name">Second Name: </label>
> <input type="text" name="second_name"><br>
> <INPUT type="submit" value="Send"> <INPUT type="reset">
> </form>
> ---------------------------------------
>
> And this is the php code (corrected according to your comments) ...
>
> --- select.php ---
> <?php
>
> $dbhost='localhost';
> $dbuser='toto';
> $dbpass='password';
> $dbname='adbname';
>
> $conn = mysql_connect($dbhost, $dbuser, $dbpass)
> or die ('Cannot connect to DB!!');
>
> mysql_select_db($dbname);
>
> $query="SELECT user_id, login, first_name, email, country FROM
> users WHERE first_name='$first_name'";
>
> $result = mysql_query($query);
>
> while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
>
> echo "Name: {$row['first_name']} <br>" .
> "Login: {$row['login']} <br>" .
> "Client Number: {$row['user_id']} <br>" .
> "Email: {$row['email']} <br>" .
> "Country: {$row['country']} <br><br>" ;}
>
> ?>
> ----------------
>
> If anyone wants to see the table I'm trying to access ..
>
> mysql> describe users;
> +-------------+-------------+------+-----+---------+----------------+
> | Field | Type | Null | Key | Default | Extra |
> +-------------+-------------+------+-----+---------+----------------+
> | user_id | int(11) | NO | PRI | NULL | auto_increment |
> | login | varchar(8) | NO | | | |
> | password | varchar(8) | NO | | | |
> | first_name | varchar(25) | NO | | | |
> | second_name | varchar(25) | NO | | | |
> | email | varchar(25) | NO | | | |
> | sex | varchar(1) | YES | | NULL | |
> | dob | date | NO | | | |
> | address1 | varchar(25) | YES | | NULL | |
> | address2 | varchar(25) | YES | | NULL | |
> | postcode | varchar(10) | YES | | NULL | |
> | state | varchar(10) | YES | | NULL | |
> | country | varchar(15) | YES | | NULL | |
> | landline | varchar(10) | NO | | | |
> | fax | varchar(10) | YES | | NULL | |
> | mobile | varchar(10) | YES | | NULL | |
> | website | varchar(25) | YES | | NULL | |
> | quote | varchar(50) | YES | | NULL | |
> +-------------+-------------+------+-----+---------+----------------+
> 18 rows in set (0.11 sec)
>
> Now if I enter say 'john' in the first field of my form and his Submit, I
> get 'Resource id #3' (to be fair, I also get this if I enter nothing before
> hitting Submit), yet if I execute the query manually ..
>
> myql> SELECT user_id, login, first_name, email, country FROM
> -> users WHERE first_name='john';
> +---------+---------+------------+-----------------------+-----------+
> | user_id | login | first_name | email | country |
> +---------+---------+------------+-----------------------+-----------+
> | 2 | john | John | joh...@gmail.com | Australia |
> +---------+---------+------------+-----------------------+-----------+
> 1 row in set (0.00 sec)
>
> So something's not right with the code, obviously..... :-(
remember where I asked /how/ you were getting $first_name and hoped it
was by using
mysql_real_escape_string( $_GET['first_name'] );
well now you have changed the form, you need to change the GET to POST
and then just do it!
$first_name = mysql_real_escape_string( $_POST['first_name'] );
if in doubt about a query thats failing, just use
var_dump( $qeury );
to see what you are passing to the DB, that would have shown up as NOT
what you were passing to the db in the command line.
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