|
|
Posted by "yanghshiqi" on 07/12/05 20:50
You can use "select u.a as u.a, v.a as v.a .."
Best regards,
Shiqi Yang
-----Original Message-----
From: adolfas [mailto:adolfas@nese.lt]
Sent: Tuesday, July 12, 2005 2:42 PM
To: php-general@lists.php.net
Subject: [PHP] Plz, help
Hi,
I have a line:
$sql="select u.*, p.name_lt as pareiga from nese_users u left join
nese_pareigos p on p.id=u.pareiga order by data desc";
As I understand there are 2 tables: nese_users and nese_pareigos
I need to know what atributes belong to what table form that line.
Thanks
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Navigation:
[Reply to this message]
|