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Having Trouble with a Basic Hit Counter

Posted by kvnsmnsn on 07/19/07 15:25

I've got a piece of PHP code that gets executed twice. The first time
through, variable <$User> is unregistered, so message "jqz cbig90"
gets printed to the screen as an error message. When I comment out
that first <system_error( $message);>, then the first time through
happens without a problem, and the second time through message
"jqz cbig93" gets printed to the screen as an error message.

At the same time I'm using variable <$hits> to keep track of how many
times this code has been executed, using the format specified on page
183 of the book _Programming PHP_ by Lerdorf and Tatroe. So the first
time through <$hits> should have value 1, and after I commented out
the first <system_error( $message);> it should have value 2. But in
this latter case the value displayed on the screen is still 1.

Does anybody know why this is happening? How can I write my code so
that the first time through this section <$hits> is 1 but the second
time through this section <$hits> is 2? Any information on this would
be greatly appreciated.

---Kevin Simonson

"You'll never get to heaven, or even to LA,
if you don't believe there's a way."
from _Why Not_

####################################################################

session_start();

global $hits;
session_register( 'hits');
++$hits;

..........<snip>..........

if( !session_is_registered( "User" ) ) {
session_register( "User" );
$User = new User();
$message = sprintf( "jqz cbig90--\$hits == %d.", $hits);
system_error( $message);
} else if( !is_object( $User ) ) {
$message = sprintf( "jqz cbig93--\$hits == %d.", $hits);
system_error( $message);
system_error( "Unable to instan_tiate User object." );
} // end if

####################################################################

Function <system_error> is just:

####################################################################

function system_error( $error ) {
die
( "<div style=\"font: normal 12px verdana;\"><b>System Error:</b>
"
. $error . "</div>" );
}

 

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