|
|
Posted by mjones on 07/29/07 16:42
On Jun 30, 4:58 am, Ben C <spams...@spam.eggs> wrote:
> On 2007-06-30, mjones <mich...@quality-computing.com> wrote:
>
> > Hi All,
>
> > I know this can be done, but I'm not a programmer. I only know HTML
> > so I'm hoping there's a simple way to do this.
>
> > If it matters, I'm using HTML 4.01 Transitional and utf-8.
>
> > I need the code because FireFox and IE6 or 7 behave differently with
> > image tags and relative positioning.
>
> > I've got an iframe over an iframe and I need to force positioning due
> > to some nasty menu code that has a mind of its own. The menu has a
> > division style with z-index:999999, too. If anyone could explain what
> > that it, it might help me. I've read about it, but still can't seem to
> > get my head around it.
>
> Basically it means it gets displayed on top of anything with a lower
> value of z-index, or auto z-index, that's also below the nearest thing
> above it in the document tree that has non-auto z-index.
>
> But often people don't realize that z-index only applies to positioned
> elements, so they set it all over the place without it doing anything.
>
> And 999999 is a silly number. Probably 9 would have been fine.
For those looking for the answer, here's what worked:
In the head -
<script language="JavaScript" type="text/javascript">
var nav = window.navigator
var browserType=nav.appName.toUpperCase()
var browserVersion=nav.appVersion
var curr_fld
if (browserType.substring(0,3)=="NET")
{ browserType="Netscape"
} else
{ browserType="Microsoft"
}
</script>
In the body -
<script language="JavaScript" type="text/javascript">
if (browserType=="Microsoft") {
document.write("WHATEVER CODE YOU WANT IF FIREFOX")
}
else
{
document.write("WHATEVER CODE YOU WANT IF IE")
}
</script>
Hope that helps,
Michele
Navigation:
[Reply to this message]
|