|
Posted by Dani on 07/31/07 19:49
<cpptutor2000@yahoo.com> schrieb im Newsbeitrag
news:1185857054.867928.107390@e16g2000pri.googlegroups.com...
> Could some PHP guru please help me? I am trying to create menus whose
> content will be extracted dynamically from a database table. What I am
> not sure about is how the information that is extracted from the
> database is to be sent to the menu.php file, if I am trying to use a
> include ... from inside another php file. Are there any simple
> examples anywhere? Any hints or suggestions would be of great help.
> Thanks in advance for your help.
hi,
if you are already using some menu.php file, than just get DB data from this
file directly (you don't need to forward it or something).
it could be something like this (for example you have some table menu with
following columns: menu_id, description, menu_order):
$sql = "SELECT menu_id, description FROM menu ORDER BY menu_order";
$result = mysql_query($sql);
while ($row = mysql_fetch_row($result)) {
print "<td>$row[1]</td>";
}
......
it is not complete, but it is quite simple..
greetz,
dani
Navigation:
[Reply to this message]
|