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Re: PHP help with if else

Posted by Steve on 08/27/07 16:52

>
> You didn't show us your SELECT statement, but if it doesn't return any
> rows, your mysql_fetch_array() call will return false - and not execute
> anything in the loop.
>
>

Here it is with the select statement. The statement DOES work, because if
there are listings in the DB they will display correctly. It's just the
if...else portion of the code that i can not get to execute.

$sql = "select ID, date, venue, street, city, state, time, cost, notes from
tblBand order by date";
$result = mysql_query($sql);


while($band = mysql_fetch_array($result, MYSQL_ASSOC))
{
$change_to_time = strtotime($band[date]);
$newdate = date('m.d.Y', $change_to_time);


if (empty($band[date])) {
echo "No shows on the calendar.";
}

else {
echo "<div id=\"line1\">$newdate - $band[venue]</div>";
echo "<div id=\"line2\">$band[street] $band[city], $band[state] - <a
href =
\"http://maps.google.com/maps?q=$band[street]+$band[city]+$band[state]\">Map</
a></div>";
echo "<div id=\"line3\">$band[notes]</div>";
echo "<div id=\"line4\">Time - $band[time], Cost - $band[cost]</div>";
echo "<hr />";
}
}

 

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