|
|
Posted by Jerry Stuckle on 08/30/07 04:14
Fred Atkinson wrote:
> On Tue, 28 Aug 2007 16:17:09 +0100, "peter" <submit@flexiwebhost.com>
> wrote:
>
>>> It returns null, which brings up a blank image.
>> then you can simply do something such as:-
>>
>> <?PHP
>> $image = getRandomImage('LL/');
>> if (is_null($image))
>> {
>> $image = '';// Set to the image you wish
>> }
>> echo "<img src='$image' height=90 width=120 alt='LL'>";
>> ?>
>>
>> in the if statement place the path and name of the image you want to use as
>> the image that will be displayed if nothing is returned from the function.
>>
>
> When I use this:
>
> <?php
> $image = getRandomImage('LL/');
> if (is_null($image))
> {
> $image = 'none.jpg';// Set to the image you wish
> }
> echo "<img src='$image' height=90 width=120 alt='LL'>";
> ?>
>
> and pull up the Web page I look at the source and I see this:
> <img src='' height=90 width=120 alt='LL'>
>
> As you can see the 'none.jpg' default file is not coded into
> the resulting HTML.
>
> Any idea why?
>
> Regards,
>
>
>
> Fred
>
Because it's returning an empty string - which is NOT the same as null.
--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
==================
Navigation:
[Reply to this message]
|