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Posted by Tom on 09/04/07 17:41
On Tue, 04 Sep 2007 00:38:22 -0700, Otis wrote...
>
>PHP is driving me mad with their idiotic way of dealing with dates and
>date conversions - unless I'm the idiot.
>
>Here's what I need:
>
>Let's assume the date is $d = "09/03/1951" - Sep 3, 1951
>
>How do I get just the year from a date like Sep 3, 1951?
>How do I get just the day from a date like Sep 3, 1951?
>How do I get just the month from a date like Sep 3, 1951?
>
>I have never been able to get PHP to deal properly with the years since
>it seems to have the stupid habit of deciding for itself whether a year
>is 2000 something or 1900 something. It apparently only wants to deal
>with 2-digit years.
>
>Here is what I have done in the past when I needed a FULL date:
>
> if ($inyear >= 2000)
> {
> $utdatenow = strftime("%d.%m.20%y", mktime($inhours, $inmins,
>$insecs, $inmonth, $inday, $inyear));
> }
> else
> {
> $utdatenow = strftime("%d.%m.19%y", mktime($inhours, $inmins,
>$insecs, $inmonth, $inday, $inyear));
> }
>
>How cumbersome!!!
>
>Isn't PHP/UNIX smart enough to know what the 4-digit year is without me
>having to jump through hoops?
>
>In Visual Basic it was simple:
>
>yr$ = Year("09/03/1951") gave me 1951
>dy$ = Day("09/03/1951") gave me 3
>mo$ = Month("09/03/1951") gave me 9
>
>Why isn't PHP as straight-forward?
>
>
>Thank you.
>
>
>Otis
Might check either of there at the PHP site. I believe the top one will give you
a string of text with the information you request. The second would give you an
array you can probably get more use out of...
http://www.php.net/manual/en/function.date.php
http://www.php.net/manual/en/function.getdate.php
Tom
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