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Posted by Satya on 09/07/07 07:28
On Sep 7, 8:49 am, J. Frank Parnell <p...@edgecity.ufo> wrote:
> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle <jstuck...@attglobal.net>
> wrote:
>
>
>
> >J. Frank Parnell wrote:
> >> Hello,
> >> So, I was wondering how to do this:
>
> >> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
> >> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
> >> }
>
> >> Thanks,
>
> >No.
>
> >However, you can use "each" to do the same thing, i.e.
>
> >reset $array1;
> >reset $array2;
>
> >for ((list($key1, $val1) = each($array1)) &&
> > (list($key2, $val2) = each($array2)) {
> >// $key1 and val1 contain the key and value for an element in $array1
> >// $key2 and val2 contain the key and value for an element in $array2
> >// Do your stuff here
> >}
>
> >It will stop as soon as you run out of elements in either array.
>
> Ah, cool, I saw similar on the php.net. Is there a way to do it so that it will
> go thru all of both, even if one runs out?
if (count ($arr1) > count($arr2)) {
$len = count($arr1);
}
else {
$len = count($arr2);
}
Now
foreach($i=0; $i < $len; $i++) {
list($key1, $val1) = @each($arr1);
list($key2, $val2) = @each($arr2);
}
What about this?
I have not checked this.
http://satya61229.blogspot.com/
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