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Re: variable

Posted by Gandalf on 09/15/07 09:22

On Sep 15, 11:07 am, gosha bine <stereof...@gmail.com> wrote:
> Gandalf wrote:
> > On Sep 15, 10:32 am, Gandalf <goldn...@gmail.com> wrote:
> >> I don't understand why this expression doesn't work:
>
> >> $var= '$_POST';
>
> >> $name= ${$var}[name];
>
> >> the ${$var}[name] expression wont return the same expression of
> >> $_POST[name].
> >> why does it happens, and how can i solve it?
>
> >> thanks
>
> > i meant to write $var ='_POST',
> > and the that ${$var}[name] wont return the same value as $_POST[name]
>
> hi
>
> this should work as expected. Care to post more code?
>
> --
> gosha bine
>
> extended php parser ~http://code.google.com/p/pihipi
> blok ~http://www.tagarga.com/blok

$var gets the value '_POST'
function create_par($var){
global $_COOKIE, $_POST, $active;

if(${$var}[no_win_from]!=0 || ${$var}[no_win_to]!=${$var}[games])
$active[0]="no_win"; else die(${$var}[games]);
if(${$var}[out_win_from]!=0 || ${$var}[out_win_to]!=${$var}[games])
$active[1]="out_win";

if(${$var}[yedaActive_2]=="true"){
if(${$var}[range_yeda1_from]!=0 || ${$var}[range_yeda1_to]!=${$var}
[games])$active[2]="range_yeda1";
}
if(${$var}[yedaActive_3]=="true"){
if(${$var}[range_yeda2_from]!=0 || ${$var}[range_yeda2_to]!=${$var}
[games]) $active[3]="range_yeda2";
}
if(${$var}[home_win_from]!=0 || ${$var}[home_win_to]!=${$var}[games])
$active[4]="home_win";
}

 

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