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Posted by J.O. Aho on 09/19/07 15:05
Bill wrote:
> Janwillem Borleffs wrote:
>> Bill schreef:
>>> Can anyone point me in the right direction. I am trying to upload jpg
>>> images and using the following piece of code
>>> $myerror = "no";
>>> $msg = "ok";
>>> $img_types = array('image/jpeg','image/jpg','image/pjpeg');
>>> if (!in_array($_FILES['imagefile']['type'],$img_types))
>>> {
>>> $msg = 'Problem: file is not jpg';
>>> $myerror = "yes";
>>> }
>>> echo $msg;
>>> When I try to download a jpg I still get the problem msg.
>>> Is there something that I am doing wrong that I cant see or is there
>>> another way to do this.
>>> Thanks in advance
>>>
>>
>> What is the output when you print $_FILES['imagefile']['type']?
>>
>>
>> JW
>
> i tried
> $newname = $_FILES['imagefile']['type'];
> echo $newname;
> and got nothing.
> Is there something I have to do to make this work
> Thanks
Try with
var_dump($_FILES);
and see what is set in the variable when an upload has been done and
it's easier to see things if you look at the webpage source code than
looking at the output in the browser (browsers don't care about new lines).
--
//Aho
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