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Posted by Surendra Singhi on 07/21/05 01:39
Hello,
(1)
When I try this code:
<?php
$var_global =" stuff";
function f1() {
global $var_global;
$var_local = array(1,2);
$var_global =& $var_local;
}
f1();
print_r($var_global);
?>
I get the output:
stuff
where as I was expecting junk value or null.
My question is that, because the array is created locally and we
pass it by reference (without copying) so on the exit of function, its value
is lost, but how does the global variable gets back its old value?
Is it something which is not defined by the PHP language reference and is
implementation specific? And in this case instead of giving the global
variable some junk value or null value, the implementation decides to store
the old values?
Thanks.
--
Surendra Singhi
http://www.spikesource.com
http://www.public.asu.edu/~sksinghi/
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