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Posted by C. on 09/27/07 16:23
On 27 Sep, 02:31, Chenky <jminche...@gmail.com> wrote:
> I've been trying to nut this error out for the last three days to no
> success. Here's the code:
>
> $usern = "myusername";
> $passw = "mypassword";
> $db="mydatabase";
>
> $link2 = @mysql_connect("localhost", $usern, $passw);
> if (! $link2) {
> die("Connect error.");
>
> }
>
> mysql_select_db($db) or die("DB Select error");
>
> $status = mysql_query("SELECT * FROM members WHERE usern='$user'");
>
> while ($display = mysql_fetch_array($status)) {
>
> print $display['usern'];
>
> }
>
> mysql_close($link2);
>
> (Obviously Ive change the real database name, user and password, but
> rest assured the real ones are correct - this i have triple and
> quadruple checked)
>
> On a whim I changed the $status variable to:
> $status = mysql_query("SELECT * FROM members WHERE usern='$user'") or
> die (mysql_error());
> and was given this error:
>
> Access denied for user 'myusername@localhost' (Using password: NO)
>
> This is what confuses me - why isn't it recognising the use of
> password? All help appreciated.
try:
error_reporting(E_ALL);
....
$link2 = mysql_connect("localhost", $usern, $passw);
and also:
error_reporting(E_ALL);
....
$link2 = mysql_connect('127.0.0.1', $usern, $passw);
If you're still stuck, try with the mysql command line client:
mysql -h localhost -u myusername -p mypassword
HTH
C.
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