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 Posted by Sebastiaan 'CrashandDie' Lauwers on 10/12/07 17:42 
worktech@gmail.com wrote: 
 
> This is not my website I am dealing with, it is a public site that 
> uses a form that has the code above.  So why can't I just pass the 
> data through the address bar?  Is there some security in place that 
> might prevent url passing of variables? 
 
No, it's just coded in a way it doesn't react to the variables you pass  
in the $_GET array, but only in the $_POST array. 
 
There is a small work around, but it has nothing to do with PHP. At  
least, not as you describe it. 
 
> If I can't do that, would writing a script that uses sockets be able 
> to accomplish this somehow?  Or is it somehow not possible without 
> using their html form 
 
Woah, hold your horses ! 
 
You don't need to use sockets to do this. If you want to retrieve data  
with your PHP server, then a little bit of cURL and it will all be over. 
 
On the other hand, from what you've explained, I understood that it's  
just *you*, client side who wants to get to a page that needs a form to  
post a bit of information. 
 
Create an html file with this code in it: 
 
<html> 
   <head> 
     <script type="text/javascript"> 
       function sendData () 
       { 
         var form = document.getElementById ("theForm"); 
         form.submit (); 
       } 
     </script> 
   </head> 
   <body onload="javascript:sendData ()"> 
     <form id="theForm" method=POST  
action="http://whateversite.com/rcon.php"> 
       <input type="hidden" name="addr" value="ADDRESSVALUE" /> 
       <input type="hidden" name="rcon" value="RCONVALUE" /> 
       <input type="hidden" name="announceflag" value="1" /> 
     </form> 
   </body> 
</html> 
 
(You will need to replace 3 values: the address of the server, and the  
values of "addr" and "rcon") 
 
When you load this page, it will automagically submit the form to the  
server, and should get you where you want. 
 
Of course, this only works if there are no cookies involved (in which  
case you will have to identify against the server before executing this  
page, within the same browser). 
 
If I misread your post, please correct me. 
 
HTH, 
 
S.
 
  
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