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Posted by Summercool on 10/19/07 02:58
On Oct 18, 7:45 pm, macca <ptmcna...@googlemail.com> wrote:
> >I wonder in PHP, can you have a function like
> > print_debug($foo);
> >and it will print out:
> >$foo is:
> >3
>
> <?php
>
> //============ Function : print_debug( arr result of get_defined_vars,
> mixed variable to debug)
>
> function print_debug($defined_vars_array, $debug){
>
> $unset_unwanted =
> array("GLOBALS","_POST","_GET","_COOKIE","_FILES");
> foreach ($unset_unwanted as $remove){
> unset($defined_vars_array[$remove]);
> }
>
> while ($element = current($defined_vars_array)) {
> if ($element == $debug) {
>
> if (is_array($debug)){
> echo '$'.key($defined_vars_array).' = <br />'.
> print_r($debug, TRUE) . "<br />";
> } else {
> echo '$'.key($defined_vars_array).' = '. $debug . "<br />";
> }
> }
> next($defined_vars_array);
> }
>
> }
>
> //============= End of Function
>
> //=========================================
> // somescript.php
>
> // Test Variable
> $test_var1 = "This is a test Variable";
> $var_test = array(1,2,3);
>
> // debug the variable by calling "print_debug()"
>
> $arr = get_defined_vars();
> print_debug($arr,$var_test);
>
> ?>
>
> Prints
>
> $var_test =
> Array ( [0] => 1 [1] => 2 [2] => 3 )
The above code doesn't seem to print anything out...
it is mainly to compare values? then what if two variables have the
same content? can it distinguish which is which?
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