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Posted by David Williams on 10/30/07 00:55
Shelly <sheldonlg.news@asap-consult.com> wrote:
Hi Shelly,
Clearly, the <?php ?php> tag way is wrong as Rik pointed out.
I was thinking that I had the <script></script> tags outside of the
initial <? ?> tags and I was writing Javascript ( the abc part ) so I needed
to get the php back out. Rik has said to think of php as writing javascript statements
..
Yes, I know, convouluted. I need a very good tutorial on how to mix javascript and
php but have not found one yet.
Also, the reason it is in a loop is because this was for testing purposes.
The real code writes a different value to diff vars.
Thanks for any more critiques.
David
And, I was trying to assign a php var value
> "David Williams" <dw149@acmex.gatech.edu> wrote in message
> news:fg5rk9$be5$1@news-int.gatech.edu...
> >
> > Can anyone see why the javascript var abc here is not getting assigned
> > the php var ("Hello")? in my code? I have tried a lot of different ways
> > but the javascript variable will not take.
> >
> >
> > Thanks,
> > David
> >
> >
> > <script>
> > var abc
> > <?php
> > $sizeof_image_array=5;
> > for($i=0;$i<$sizeof_image_array;$i++)
> > {
> >
> > $temp_image_name="Hello";
> > echo 'abc=<?php echo $temp_image_name;?>;';
> > echo 'alert(abc);';
> >
> > }
> > ?>
> > </script>
> >
> Why do you have <?php followed by <?php ? Don't you mean
> echo 'abc = "' . $temp_image_name . '";' ;
> Also, why is this in a loop?
> Shelly
--
David Williams
Georgia Institute of Technology, Atlanta Georgia, 30332
Email: dw149@prism.gatech.edu
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