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Posted by pgt on 10/31/07 23:32
"Rik Wasmus" <luiheidsgoeroe@hotmail.com> wrote in message
news:op.t0203pi85bnjuv@metallium.lan...
On Wed, 31 Oct 2007 23:01:45 +0100, pgt <pgtnot@gmail.not> wrote:
> I have a working couple of pages (form submits 2 variables to the second
> page using GET).
>
> page1 has two dropdowns (generated from MySQL db).
>
> page2 retrieves info from the database accordingly, depending on the
> passed
> variables. Works fine.
>
>
> I need to ensure that the user has actually selected both variables on
> page1
> from each of the drop down options on page1.
>
> empty() seems unable to do this because the default drop down options are
> "Select one", "Select the other".
>
> so on page2, if the user has NOT made any choices:
>
> echo "Values passed to GET method:<br />\n";
> reset ($_GET);
> while (list ($key, $val) = each ($_GET)) {
> echo "$key => $val<br />\n";
> }
>
> gives me:
> Select one
> Select the other
>
>
> I can not see how to use empty() or isset() to resolve this, so...
>
> Any ideas how to ensure the user has selected something from both options
> (without javascript)?
>
> I couldn't find anything in the manual but assume I'm looking in all the
> wrong places for this.
Give the option a value 0 (well, it's more transparant/reliably checked
then for the string 'Select one', and check if(!isset($_GET['option1']) ||
$_GET['option1'] = 0) echo 'Please select an option.';
Still missing something here then:
page1
<select name="this">
<option value="0">Select one</option>
</select>
<select name="that">
<option value="0">Select the other</option>
</select>
page2
if (!isset($_GET['var1']) || $_GET['var1'] = "0")
{ echo 'Go back and select the first choice.'; }
if (!isset($_GET['var2']) || $_GET['var2'] = "0")
{ echo 'Go back and select your second choice.'; }
What am I missing with this please?
Thanks for any help.
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