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Re: binary and & vs &=

Posted by Darko on 11/09/07 18:29

On Nov 9, 7:11 pm, "Steve" <no....@example.com> wrote:
> "Darko" <darko.maksimo...@gmail.com> wrote in message
>
> news:1194624540.774587.257620@o3g2000hsb.googlegroups.com...
>
> > On Nov 9, 3:35 pm, joshuajnoble <joshuajno...@gmail.com> wrote:
> >> Is there any difference between doing:
>
> >> $var & 0x80;
>
> >> and
>
> >> $var &= 0x80;
>
> >> I've seen the second, using the &= in production code, but on my local
> >> machine it errors out. Any thoughts?
>
> > $var &= 0x80 <=> $var = $var & 0x80
>
> perhaps <=> is a non-standard equality to the op. you mean that both
> accomplish the same thing...they are just two different ways of writing the
> same thing, right?

In math, <=> means "is equivalent to".

 

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