Posted by Olaf Schinkel on 11/19/07 11:25

Hi!

> //$sql="INSERT INTO photos (image_nom,image_vignette,image_fichier)
> //VALUES ('$nom_fichier','mavignette','$emplacement_fichier')";
> //$result=mysql_query($sql,$connexion) or die(mysql_error());
What about a:
echo $sql;
Maybe wrong chars in it.
Post the whole errormessage here.

Olaf

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