|
|
Posted by Steve on 11/20/07 22:03
"Rik Wasmus" <luiheidsgoeroe@hotmail.com> wrote in message
news:op.t13ogdmp5bnjuv@metallium.lan...
On Tue, 20 Nov 2007 17:08:14 +0100, Steve <no.one@example.com> wrote:
>
> "MW" <bulk@spandan.com> wrote in message
> news:13k5vaqt73n2e7@corp.supernews.com...
>> I wanted to know if it was possible to use the "Variable variable"
>> syntax to access a public variable inside a class. For example, using
>> the code below, I am trying to set the value of variable $var_a in the
>> class Cls from outside the code, but want to be able to use the same
>> code to assign a value to $var_b. i.e. I don't want the variable's name
>> defined in the code.
>>
>> class Cls {
>> public $var_a;
>> public $var_b;
>> }
>>
>> $x=new Cls;
>> $y="var_a";
>> $x->$y="Hello"; // want this to translate to $x->var_a="Hello"
>>
>> I tried using $x->{$y}="Hello" but that did not work either...
>
> try:
> $x->$$y = 'hello'
> or:
> $x->${$y} = 'hello'
=============
> Which would require you have a $var_a set outside the class:
>
> $y="var_a";
> $var_a = "foo";
which is the exact thing his example shows.
> This: $x->$$y = 'hello'
> Is this: $x->$var_a = 'hello'
> Is this: $x->foo = 'hello'
> As the OP allready stated, his original code just plainly works.
right...but please note, i responded before he remarked that his code *did*
work. so, to me, it makes no difference.
btw, rik...PLEASE set your newreader to PROPERLY mark-up/indent your
replies. it's a pain in the ass to respond to you since i have to manually
put in > for everything you type...just so everyone can tell where my
response goes in all that mess.
thanks.
Navigation:
[Reply to this message]
|