|
|
Posted by Steve on 12/19/07 17:43
"Steve" <no.one@example.com> wrote in message
news:qmcaj.44$Tt5.41@newsfe07.lga...
>
> "Logos" <tyler.style@gmail.com> wrote in message
> news:629d3852-7498-474c-9ed7-de84ec3e98d5@e25g2000prg.googlegroups.com...
>> On Dec 13, 3:16 pm, Michael Fesser <neti...@gmx.de> wrote:
>>> .oO(gosha bine)
>>>
>>> >in addition to what's already said, there's no need to use references
>>> >in php5.
>>>
>>> At least when working with objects. But nevertheless
>>>
>>> $foo = new Test();
>>> $a = $foo;
>>> $b = &$foo;
>>>
>>> are still different things, even in PHP 5. In some particular situations
>>> this might become an issue.
>>>
>>> Micha
>>
>> Oooo...errr...ummm...could someone explain how exactly those are
>> different when using PHP5, then, please? If everything is done by
>> reference for objects, then to me $a and $b both look like pointers to
>> an object.
>>
>> And...are objects always passed by reference to functions in PHP5,
>> then?
>
> alright, get ready for a ton of flamage here after i'm done...
>
> first, to be correct and accurate...objects are passed to functions by
> reference, objects in arrays are by reference (i.e. when using foreach),
> etc., etc.. variable assignment is by value. while $b = &$foo behaves like
> a pointer in *every* way, in php there are no true c-style pointers. $b is
> just an alias for $foo, a nickname...because of the amphersand (&). make
> sense?
here's a link for you to read having much discussion about referencing. in
particular, i have used some of the hacks shown there and have made a few of
my own based on the descriptions of how php is handling referencing in
different situation.
hth.
http://us.php.net/language.references.pass
Navigation:
[Reply to this message]
|