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Re: difficult query

Posted by Betikci Boris on 12/21/07 17:13

On Dec 21, 7:09 pm, Betikci Boris <pard...@gmail.com> wrote:
> On Dec 21, 10:43 am, Tarscher <tarsc...@gmail.com> wrote:
>
>
>
>
>
> > Hi all,
>
> > I have events containing attendees (events has many attendees). The
> > attendee table tells whether a user will attend the event or not. I
> > want to build a query that returns all the different events to a user
> > and if he will attend the event or not (or hasn't filled it in yet)
>
> > the returned result could be something like:
>
> > event.id     attendees.user_id     attendee.present
> >    1                1                      0
> >    2                1
> >    3                1                      1
>
> > Please note that attendee.present can be null if the user didn't yet
> > tell if he would come to the event.
>
> > Can this be done?
>
> > thanks
> > Stijn
>
> There is no need to define events table, define attended events in
> users table in arrays;
>
> $events_attended=array("1","5","3"); and goes so on..- Hide quoted text -
>
> - Show quoted text -

Addition: You may want to store the date store date as the key... or
use more complex multi-dimentional array to store all -date -event -
result, etc..

 

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