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Posted by Jerry Stuckle on 06/11/84 12:00
Ratfish wrote:
> On Jan 16, 4:06 am, Jerry Stuckle <jstuck...@attglobal.net> wrote:
>> Ratfish wrote:
>>> I'm getting a "2014:: Commands out of sync; you can't run this command
>>> now" error on a php page when I try to call a second stored procedure
>>> against a MySQL db. Does anyone know why I might be getting this
>>> error? The error doesn't occur on my development box where I use the
>>> 'root' db user, but does occur in production where I'm using a non-
>>> root user record to establish a connection. I'm essentially opening a
>>> connection at the top of the php page and then calling multiple stored
>>> procedures to fetch data. When I call the 2nd stored procedure I'm
>>> getting the error. Any info would be greatly appreciated.
>>> Aaron
>> Sorry, my crystal ball is in the shop. Since you didn't post any code,
>> I find it impossible to tell what's wrong.
>>
>> --
>> ==================
>> Remove the "x" from my email address
>> Jerry Stuckle
>> JDS Computer Training Corp.
>> jstuck...@attglobal.net
>> ==================
>
>
> Here's the code that fails:
>
> // load the entertainment record
> $sql = "call sps_entertainment(?)";
> $stmt = $link->prepare($sql);
> if ($link->errno) {die($link->errno.":: ".$link->error);}
>
> $stmt->bind_param("i", $EntId);
>
> // execute the statement
> $stmt->execute();
> if ($link->errno) {die($db->errno.":: ".$link->error);}
>
> //if ($result = $link->store_result()) {
> if ($stmt->bind_result($FEntId,
> $FCreateDate,
> $FCreateUser,
> $FModifyDate,
> $FModifyUser,
> $FEntTypeCode,
> $FEntName,
> $FURL,
> $FPictureQualityCode,
> $FPictureResolutionCode,
> $FRevenueSourceCode,
> $FEntDesc,
> $FEntFullDesc,
> $FSiteStatusCode,
> $FZombiiRatingCode,
> $FEntIconId))
> {
> if ($stmt->fetch())
> {
> $stmt->free_result();
> $stmt->close();
> ?>
> do some html here
> <select id="ddlEntIcon" name="ddlEntIcon">
> <option value="*" >(Not Specified)</option>
> <option value="NEW" >(Upload new image...)</option>
> <?php
> $sql = "call sps_entertainment_icons()";
> $stmt = $link->prepare($sql);
> if ($link->errno) {die($link->errno.":: ".$link->error);}
> // execute the statement HERE'S WHERE I THINK THE ERROR IS OCCURING!
> $stmt->execute();
> if ($link->errno) {die($db->errno.":: ".$link->error);}
> $stmt->bind_result($EntIconId, $EntIconName);
> while ($stmt->fetch())
> {
> if ($FEntIconId != "" && $FEntIconId == $EntIconId) {
> echo "<option value=\"" . $EntIconId . "\" selected>" .
> $EntIconName . "</option>\n";
> }
> else {
> echo "<option value=\"" . $EntIconId . "\">" . $EntIconName . "</
> option>\n";
> }
> }
> $stmt->free_result();
> $stmt->close();
> ?>
> </select>
>
>
OK, what is sps_entertainment returning?
If it's returning more than one row, you need to continue fetching until
they're all returned.
Also, I see if it returns no rows, you're not freeing the result. You
still have to free the result, even if no rows are returned.
--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
==================
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