You are here: Re: [PHP] Help with a Parse Error « PHP « IT news, forums, messages
Re: [PHP] Help with a Parse Error

Posted by Edward Vermillion on 08/01/05 16:09

Tom Chubb wrote:
> I have changed it a bit, and don't have the old code now!!!
> I saw a post which identified a problem using isset when $var = ""; as
> it returns true, so I changed my code to use...
>
> if ($_GET['id'] != "")
> { $article="$id.php";
> if (file_exists($article)) { include $article; }
> else { echo "The article you've requested does not exist!"; }
> }
> else {
> echo "No article selected";
> }
>
> This works fine, except that when the url is www.mysite.com/index.php
> I get the following error...
>
> Notice: Undefined index: id in
> /home/5217/tomchubb/public_html/index.php on line 14
> No article selected
>
> I kmow this will disappear when I turn off error reporting, but how
> can I suppress it properly?
>
>
> On 31/07/05, Edward Vermillion <evermillion@doggydoo.net> wrote:
>
>>Tom Chubb wrote:
>>
>>>I am trying to create my own news system and to start with I'm using
>>>static news pages until I get the db working properly.
>>>I'm using the following code:
>>>
>>><?php
>>>if(!isset($_GET['id']))
>>>{ $article="$id.php"
>>> if (file_exists($article)) { include $article; }
>>> else { echo "The article you've requested does not exist!"; }
>>>}
>>> else { echo "You did not select an article"; }
>>>?>
>>>
>>>I am testing using the following links...
>>>
>>>www.myurl.co.uk/index.php
>>>www.myurl.co.uk/index.php?id=1
>>>www.myurl.co.uk/index.php?id=2
>>>
>>>When I try the first one, I'd expect it to say you did not select an
>>>article, but it says
>>>
>>>
>>>Notice: Undefined variable: id in
>>>/home/5217/tomchubb/public_html/index.php on line 15
>>>The article you've requested does not exist
>>>
>>>
>>>When I try the third link, I would expect it to say The article
>>>you've requested does not exist! but it says:
>>>
>>>Parse error: parse error in /home/5217/tomchubb/public_html/index.php on line 16
>>>
>>>Lines 15 & 16 are:
>>>if (file_exists($article)) { include $article; }
>>>else { echo "The article you've requested does not exist!"; }
>>>
>>>I don't understand why this isn't working and I've tried looking into
>>>this for 2 hours!
>>>Can anyone tell me where I'm going wrong please?
>>>
>>>Thanks,
>>>
>>>Tom
>>
>>What I notice is that the first error says it's on line 15, then you
>>give lines 15 and 16 in the second example but line 15 doesn't have "id"
>>in it. Are you sure your looking at the right lines? Try posting the
>>whole script and maybe someone can catch the problem.
>>
>
>
>
I always use

if(!empty(...)) {

it takes care of empty variables and variables that haven't been set at
the same time. :)

 

Navigation:

[Reply to this message]


Удаленная работа для программистов  •  Как заработать на Google AdSense  •  England, UK  •  статьи на английском  •  PHP MySQL CMS Apache Oscommerce  •  Online Business Knowledge Base  •  DVD MP3 AVI MP4 players codecs conversion help
Home  •  Search  •  Site Map  •  Set as Homepage  •  Add to Favourites

Copyright © 2005-2006 Powered by Custom PHP Programming

Сайт изготовлен в Студии Валентина Петручека
изготовление и поддержка веб-сайтов, разработка программного обеспечения, поисковая оптимизация