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Posted by Dan Gelder on 06/12/95 12:01
On Jan 26, 8:46 pm, Sebastian Lisken <Sebastian.Lis...@Uni-Bielefeld-
deletethis.de> wrote:
> Dan Gelder <daniel.w.gel...@gmail.com> wrote:
>
> > no, that just turns
> > /home/.machine/user/site.com/work/january/phpstuff/includer.php
> > into
> > /home/.machine/user/site.com/work/january/phpstuff/
>
> > and you can read my post to understand why that brings me no closer
> > than before.
>
> > What I need to know, I guess, is a way to get the official root folder
> > so I have
> > /home/.machine/user/site.com/
>
> > And then I can match the strings?? Can't say how to solve it yet.
>
> Wouldn't $_SERVER["SCRIPT_NAME"] do what you are looking for? Don't use
> $_SERVER["PHP_SELF"] because that can contain so-called "additional path
> information" that users could be adding to the script's URL in some
> circumstances (/january/phpstuff/includer.php/extra/stuff) and which,
> incidentally, makes $_SERVER["PHP_SELF"] a value that should not be
> trusted. Mind you, perhaps it's better to regard all of $SERVER as
> untrusted just to err on the side of caution.
>
> Sebastian Lisken
I know not to trust $_SERVER too far, but it doesn't matter, because I
am interested in finding the *included file*'s location, not the base
script. IE:
------
------ folder1/file1.php:
------
echo "Here is an image from another folder:";
include '/folder2/file2.php';
------
------ folder2/file2.php:
------
function getGlobalPrefix()
{
//this is what I need to write:
//it takes the data in __FILE__ and somehow turns that into 'http://
mySite.com/folder2/'
}
echo "<img src='" . getGlobalPrefix() . "/myGreatImage.gif'>";
------
OK, does it make sense now?? :-)
Dan
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