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Posted by AnrDaemon on 09/28/15 12:01
Greetings, Dan Gelder.
In reply to Your message dated Sunday, January 27, 2008, 05:08:15,
>> > no, that just turns
>> > /home/.machine/user/site.com/work/january/phpstuff/includer.php
>> > into
>> > /home/.machine/user/site.com/work/january/phpstuff/
>>
>> > and you can read my post to understand why that brings me no closer
>> > than before.
>>
>> > What I need to know, I guess, is a way to get the official root folder
>> > so I have
>> > /home/.machine/user/site.com/
>>
>> > And then I can match the strings?? Can't say how to solve it yet.
>>
>> Wouldn't $_SERVER["SCRIPT_NAME"] do what you are looking for? Don't use
>> $_SERVER["PHP_SELF"] because that can contain so-called "additional path
>> information" that users could be adding to the script's URL in some
>> circumstances (/january/phpstuff/includer.php/extra/stuff) and which,
>> incidentally, makes $_SERVER["PHP_SELF"] a value that should not be
>> trusted. Mind you, perhaps it's better to regard all of $SERVER as
>> untrusted just to err on the side of caution.
>>
>> Sebastian Lisken
> I know not to trust $_SERVER too far, but it doesn't matter, because I
> am interested in finding the *included file*'s location, not the base
> script. IE:
> ------
> ------ folder1/file1.php:
> ------
> echo "Here is an image from another folder:";
> include '/folder2/file2.php';
> ------
> ------ folder2/file2.php:
> ------
> function getGlobalPrefix()
> {
> //this is what I need to write:
> //it takes the data in __FILE__ and somehow turns that into 'http://
> mySite.com/folder2/'
> }
> echo "<img src='" . getGlobalPrefix() . "/myGreatImage.gif'>";
> ------
> OK, does it make sense now?? :-)
You has an advice but don't get it right.
$dir = dirname(__FILE__); // current script location
if(stripos($_SERVER['DOCUMENT_ROOT'], $dir) === 0)
{
$dir = substr($dir, strlen($_SERVER['DOCUMENT_ROOT']));
echo("<img src=\"{$dir}/image_in_the_same_location_as_script\"/>");
}
--
Sincerely Yours, AnrDaemon <anrdaemon@freemail.ru>
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